If the pressure of a gas at constant volume is 35 atm at 100"C, what will the pressure be if the temperature is changed to 250C?
If the pressure of a gas at constant volume is 35 atm at 100"C, what will the pressure be if the temperature is changed to 250C?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
The pressure increases by 0.03 atm.
This problem involves Gay-Lussac's Law. It states that the pressure exerted on the sides of a container by an ideal gas of fixed volume is proportional to its temperature.
P
1
T
1
=
P
2
T
2
P
1
= 1.00 atm;
T
1
= (20.0 + 273.15) K = 293.2 K.
P
2
= ?;
T
2
= (30.0 + 273.15) K = 303.2 K.
We know
P
1
,
T
1
, and
T
2
. Thus, we can calculate
P
2
.
P
2
=
P
1
×
T
2
T
1
= 1.00 atm ×
303.2
K
293.2
K
= 1.03 atm
Δ
P
=
P
2
–
P
1
= (1.03 -1.00) atm = 0.03 atm
The pressure increases by 0.03 atm.
This makes sense. The temperature increases by 10 parts in 300 or 3 parts in 100 (3 %). So the pressure should increase by about 3 % (0.03 atm).
Answer:
I don't know the answer.
Explanation:
Please do me brilliant and follow me.