If the speed of a vehicle is reduced by 10%, by how much the KE changes?
Home
/
If the speed of a vehicle is reduced by 10%, by how much the KE changes?
If the speed of a vehicle is reduced by 10%, by how much the KE changes?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Firstly,
let mass=m
velocity=v
KE=1/2 (mv^2)
latter,
mass=m
velocity=[v-{v×(10/100)}]
=9v/10
Now,
KE=1/2×m×(9v/10)^2
Change in KE={1/2mv^2}-{1/2×m×(9v/10)^2}
=1/2m(19v^2/100)
%change in KE=([1/2m(19/100)v^2]/[1/2mv^2])×100
=19%
THANK YOU
Answer:
pls follow me plssss.....