if the sum of two number is 42 and their product is 437, then find the absolute difference between the numbers?with soluction full
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if the sum of two number is 42 and their product is 437, then find the absolute difference between the numbers?with soluction full
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Answer:
Step-by-step explanation:
x+y = 42 (Given)
xy = 437 (Given)
Thus, solving for one variable in terms of the other -
x = 42-y
= (42-y)y = 437
= -y²+42y = 437
= y²-42y = -437
= y²-42y+437 = 0
Using the formula of quadratic equation y = -b ±√(b²-4ac)/ 2a
= y = 42 ±√((-42)²-4(1)(437))/2
= y = 21 ±(√(1764 - 1748))/2
= y = 21 ±(√16)/2
= y = 21 ± 4/2
= y = 21 ± 2
= y = 21 or 23
If y = 21 then x+21 = 42 and x = 21
If y = 23 then x+23 = 42, x=19
x= 19, y = 23
Difference: 23-19 = 4
Answer:
Absolute difference between the numbers = |x-y|=4
Step-by-step explanation:
Let x , y are two numbers,
sum of two numbers = 42
=> x+y = 42 ---(1)
Product of two numbers =437
=> xy = 437 ---(2)
/* We know the algebraic identity:
(a-b)² = (a+b)²-4ab */
Therefore,
Absolute difference between the numbers = |x-y|=4
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