if the term of an Arithmetic progression exceeds its 10th term by 7. Find the common difference
if the term of an Arithmetic progression exceeds its 10th term by 7. Find the common difference
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An = a +( n-1) d
So, A10 = a + 9d
And, A17 = a + 16d
Now, As per the question,
A17 - A10 = 7
a + 16d - (a+9d) = 7
7d = 7
d = 1.
So, the common difference is 1.
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17th term of an A.P t17 = a + (17-1)* d = a+16d.
10th term of an A.P t10 = a + (10-1) * d = a+9d.
Given, 17th term of an AP Exceeds its 10th term by 7.
(a+16d) - (a+9d) = 7
a+16d - a - 9d = 7
16d - 9d = 7
7d = 7
d = 1.
The common difference is 1.