If the zeroes of the polynomial x²+ (a+1) x + b are ‒ 2 and 3 , then
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If the zeroes of the polynomial x²+ (a+1) x + b are ‒ 2 and 3 , then
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Step-by-step explanation:
zero's= -2, 3
polynomial:
(x-3)(x+2)= x² - x - 6
now, x² - x - 6 is equal to x²+ (a+1) x + b
so,
-1 = a + 1; a = -2
-6 = b
Hence, a = -2 and b = -6
hope it helps(•‿•)