If three cubes of side 'a' are joined end to end the surface area of the new cuboid formed is:
(a)16a^2
(b)12a^2
(c)14a^2
(d)18a^2
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If three cubes of side 'a' are joined end to end the surface area of the new cuboid formed is:
(a)16a^2
(b)12a^2
(c)14a^2
(d)18a^2
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Step-by-step explanation:
Answer is 12a^2 ..
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