If triangle ABC is right angled at C, then the value of sec (A+B) is.... ........
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If triangle ABC is right angled at C, then the value of sec (A+B) is.... ........
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Answer:
Given: C=90°
A+B+C=180 (Sum of angles in Δ)
A+B+90=180
=>A+B=90
sec (A+B)= Sec 90° = 0
hope it helps u......^_^
Answer:
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