if x^7+3x^5+100 is divided by x-1,then find the remainder
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if x^7+3x^5+100 is divided by x-1,then find the remainder
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x-1=0
So ,
x=1
p(1)=1^7 + 3(1)^5 + 100
p(1) = 1 + 3 + 100
p(1) = 104 .........
Answer:
find the quotient 24.06 divided by 100