if X+x^3+k is exactly divisible by x-2 than find k
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Answer:
If x^3+6x^2+4x+k is exactly divisible by x+2 then we can say- (-2)^3+6(-2)^2+4(-2)+k=0
or, -8+24-8+k=0
or,k+8=0
or, k=(-8)