If (x+y) = 6 and x² - y²- 4^8 find (x-y) (x+y) = x² - y²
class 8
cbse
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If (x+y) = 6 and x² - y²- 4^8 find (x-y) (x+y) = x² - y²
class 8
cbse
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Answer:
hi friend, ez question , mark me brainliest for further help
Step-by-step explanation:
we know,
[tex](a-b)^2= a^2+b^2-2ab\\[/tex]
so we can write it as,
[tex](a-b)^2 + 2ab = a^2+b^2\\or\\(a-b)^2 - (a^2+b^2) = -2ab[/tex] (KEEP THESE FORMULAS IN MIND, THEY WILL HELP YOU TO SOLVE HIGHER QUESTIONS)
SO,
according to question,( which isnt very clear try writing question properly)
6^2= (x^2+y^2) + 4^8
36-(x^2+y^2) = 4^8
-(x^2+y^2) = (65536 - 36)
-(x^2+y^2) = 65500
x^2+y^2= -65500
FROM NOW ON, WRITE THE QUESTION PROPERLY