if you provide with three beakers, beaker A contains distilled water, beakers B contains a basic solution and Beaker Contains an acidic solution.how will you identify the contents of each beaker if have only blue litmus paper?
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if you provide with three beakers, beaker A contains distilled water, beakers B contains a basic solution and Beaker Contains an acidic solution.how will you identify the contents of each beaker if have only blue litmus paper?
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➡First let us see the properties of all materials in the beakers :
✔ ACIDS : Turn blue litmus to red .
✔BASES: Turn Red litmus blue .
✔Distilled Water : Neutral ( no effect )
⏪So Now we have only a Blue litmus paper . So We shall first dip it in all the beakers one by one . When dipped in an acidic medium, it will turn RED while in the other two mediums it remains unchanged . So now we would get a red litmus paper . Then , dip this red litmus in the remaining mediums and it will turn BLUE in the basic medium . The remaining one will be Distilled water.
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Well if you have blue litmus paper then you can easily identify the acidic solution
And now when we have got the acidic solution
SO try making reaction between each of the other 2 solutions and the acid
Both are basic according to the acid as if the acid has
Ph less than 7
Distilled water has
Ph equal to 7
Base has
Ph more than 7
SO according to an acid each of them is basic
So take a few drops from the Acid as well as the other 2 solutions
And make reaction between the Acid and Each of the solution
One by One
Separately
Now the reaction producing more heat will be the Base
And the other will be distilled water.
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