If zeroes of x²– kx + 6 are in the ratio 3:2, find k.
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The zeroes are 3x and 2x.
Sum of the zeroes = 3x + 2x = 5x which is equal to kSo,5x = k
Product of zeroes = 3x(2x) = 6x² which is equal to 6So,6x² = 6x = -1 / 1
Now, plugging the value of x in 5x = k,5(1) = k or 5(-1) = kk = 5 or -5
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