II. A rectangular held is 15 m long and 10 m wide, Another rectangular held having the same
perimeter has its sides in the ratio 4: 1. Find the dimension of the rectangular
Area
enclosed
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II. A rectangular held is 15 m long and 10 m wide, Another rectangular held having the same
perimeter has its sides in the ratio 4: 1. Find the dimension of the rectangular
Area
enclosed
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Answer:
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A rectangular field is 15 m long and 10 m wide. Another rectangular field having the same perimeter has its sides in the ratio 4:1. Find the dimension of the rectangular field.
Length of the field = 15 m
Width of the field = 10 m
Perimeter
= 2(Length+Width) m
= 2(15+10) m
= 2×25 m
= 50 m
Perimeter of both the fields are equal.
So, perimeter of the other field = 50 m
Let its length and width are 4x m and x m respectively.
According to condition,
2(4x+x) = 50
➳ 2×5x = 50
➳ 10x = 50
Divide both sides by 10.
➳ 10x÷10 = 50÷10
➳ x = 5
x = 5
Length = 4x m = (4×5) m = 20 m
Width = x m = 5 m
The length and width of the other field are 20 m and 5 m respectively.
2(4x+x) = 50
➳ 2(20+5) = 50
➳ 2×25 = 50
➳ 50 = 50
So, L.H.S = R.H.S.
Hence, verified.