(ii) cos 90° + cos²45° sin 30° tan 45°
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(ii) cos 90° + cos²45° sin 30° tan 45°
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Answer:
cos 90°+cos²45°×sin 30°×tan 45°.
cos 90°=0.
cos²45°=(1/√2)²=1/2.
sin 30°=1/2.
tan 44°=1.
cos 90°+ cos²45°×sin 30°×tan 45°=0+(1/2)×(1/2)×(1).
cos 90°+cos²45°×sin 30°×tan 45°=0+(1/4)×(1).
cos 90°+cos²45°×sin 30°×tan 45°=0+1/4.
cos 90°+cos²45°×sin 30°×tan 45°=1/4.
I don't know trigonometry perfectly, then also I tried to solve it in my own way.
I think this is your answer.