in a bag there are blue and red sweets the ratio of blue sweets to red sweets is 5:3 what fraction of the sweets are blue
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in a bag there are blue and red sweets the ratio of blue sweets to red sweets is 5:3 what fraction of the sweets are blue
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Answer:
Let the common ratio between blue and red sweets be x
Then,
Number of blue sweets = 2x
Number of green sweets = 7x
If the common ratio between the green and red sweets be y
Then,
Number of green sweets = 3y
Number of red sweets = y
Here the number of green sweets must be equal
Therefore,
7x=3y7x=3y
Also the sum of all of them is 140
Thus,
2x+3y+y < 1402x+3y+y<140
\implies 2x+4y < 140⟹2x+4y<140
\implies x+2y < 70⟹x+2y<70
\implies x+2\times\frac{7x}{3} < 70⟹x+2×
3
7x
<70
\implies 3x+14x < 210⟹3x+14x<210
\implies 17x < 210⟹17x<210
\implies x < \frac{210}{17}⟹x<
17
210
\implies x < 12.36⟹x<12.36
x should be a whole number
Therefore, x=12x=12
And the sum of all the sweets will be 136
Therefore,
y=\frac{7\times 12}{3}y=
3
7×12
\implies y=28⟹y=28
Thus the greatest possible number of red sweets is 28
Hope this helps.
Answer:
1 In a bag there are blue sweets and red sweets. The ratio of blue sweets to red sweets is 5:3. What fraction of the sweets are blue? 5 parts Blue parts in Total. 8.
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