in a chemical, oxygen , carbon and nitrofen are in the rate 8:5:3. If the actual amount of nitrogen is 21gm find the mass of the chemical
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in a chemical, oxygen , carbon and nitrofen are in the rate 8:5:3. If the actual amount of nitrogen is 21gm find the mass of the chemical
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Ratio of O, C, N in a chemical compound is 8:5:3
Mass of N in it is 21g.
Let the common in the ratio be 'x'.
So, Mass of O=8x
mass of C=5x
mass of N=3x
3x=21 ⇒x=7
So, mass of O=8*7=56
mass of C=5*7=35
mass of chemical compound=56+35+21=112g