in a hot water heating system, there is a cylindrical pipe of length 28 m and diameter of 5 cm. Find the total radiating surface in the system
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in a hot water heating system, there is a cylindrical pipe of length 28 m and diameter of 5 cm. Find the total radiating surface in the system
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hope this helps mate..
Step-by-step explanation:
r= 5/2=2.5cm=0.025m
h=28m
total radiating surface of the system = total surface of the cylinder
=2×22/7×r(h+r)
=2×22/7×0.025(28+0.025)m^2
=44×0.025×28.025/7m^2
=4.4m^2