In a parallelogram ABCD, E and F are the mid points of sides AB and CD
respectively. Show that the line segment AF and EC trisect the diagonal BD. I need with a near explanation plz
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In a parallelogram ABCD, E and F are the mid points of sides AB and CD
respectively. Show that the line segment AF and EC trisect the diagonal BD. I need with a near explanation plz
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Answer:
AE=CF
Step-by-step explanation:
GIVEN:-E and F are the mid point of sides AB and CD of the parallelogram ABCD whose diagonal is BD. AE =CF. Thus, a pair of opposite sides os a quadrilateral AECF are parallel and equal . Hence, AF and CE trisect the diagonal
Answer:
in this AE=CF...
Step-by-step explanation:
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