In a two digit number the unit digit is four times the ten digit and the sum of the two digit is 10.find the number.
In a two digit number the unit digit is four times the ten digit and the sum of the two digit is 10.find the number.
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Step-by-step explanation:
Let number at unit place be x.
And digit at tens place y.
The number=10y+x
According to question,
x=40y. ....,..........1
x+10y=10…....………2
Multiply equation 2 by 4
4x+40y=40… ........3
x-40y=0……………4
Adding
4x+40y=40
+. x-40y=0
=x=8
put in equation 4
y=2
✬ Number = 28 ✬
Step-by-step explanation:
Given:
To Find:
Solution: Let the tens digit be x.
∴ Unit's digit = 4 times of x = 4x
Therefore the number will be x + 4x = 10
x + 4x = 10
5x = 10
x = 10/5
x = 2
∴ Tens digit = x = 2 and
Unit's digit = 4x = 4(2) = 8
Hence, The required number is (10 x 2 + 8) = 28.