In ∆ABC, angle A = 50° and the external bisector angleB and angle C meet at O as shown in the figure. The measure of angle BOC is?
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In ∆ABC, angle A = 50° and the external bisector angleB and angle C meet at O as shown in the figure. The measure of angle BOC is?
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Answer:
Here is your answer!
Step-by-step explanation:
boc=90-1/2(A)
according to question
boc=90-1/2(50)
boc=90-25
boc=65.
Solution :-
given that,
→ ∠A = 50°
Also, the external bisector ∠B and ∠C meet at O .
So,
→ ∠BOC = 90° - (1/2)∠A
→ ∠BOC = 90° - (1/2)50°
→ ∠BOC = 90° - 25°
→ ∠BOC = 65° (b) (Ans.)
P r o o f :- ∠BOC = 90° - (1/2)∠A .
Refer to this l i n k :- In the figure along side, BP and CP are the angular bisectors of the exterior angles BCD and CBE of triangle ABC. Prove ∠BOC = 90° - (1/2)∠A .
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