In ∆ABC, if DE || BC and DE : BC = 5 : 8, then find the ratio of areas of trapezium BCED and ∆ABC.. PLEASE HELP ASAP
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In ∆ABC, if DE || BC and DE : BC = 5 : 8, then find the ratio of areas of trapezium BCED and ∆ABC.. PLEASE HELP ASAP
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Answer.
Ar(ADE) ~ Ar(ABC)
Therefore,
ar(ADE)=DE^2
ar(ABC) BC^2
= 25
64
NOW,
areas of trap.BCDE=Ar(ABC)-Ar(ADE)
=64-25=39
Now,
ratio of areas of trap.BCDE and ABC= 39:64
Step-by-step explanation:
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