In ΔABC,right angled to B.BD perpendicular to AC.Prove that ΔBDC similar to ΔABC.
Share
In ΔABC,right angled to B.BD perpendicular to AC.Prove that ΔBDC similar to ΔABC.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
In triangle BDC and triangle ABC
BD = BD. ( common)
angle BDC = angle BDA ( both angles are 90°)
CD = AD. ( D is the mid point of AC as BD is perpendicular to AC.
So,
triangle BDC is similar to triangle ABC .
Answer:
mai toh mstt hu aap batao