In an AP if the 3rd term is 12 and 50th term is 106 then find its 29th term
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In an AP if the 3rd term is 12 and 50th term is 106 then find its 29th term
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Answer:
a3-12
a50-106
a29-?
a+2d=12
a+49d=106
______–-–--
-47d= -94
d= 2
a+2d=12
a+2(2)=12
a+4=12
a=12-4
a=8
a+29d
8+29(2)
8+56
=62
We know, an= A+(n-1)d
Therefore, a3 = a+(3-1)d =a+2d
Therefore, a50= a+49d
We know that, a+2d=12
Therefore, a=12-2d
2nd eqn
a+49d=106
Putting value of a,
12-2d+49d=106
=12+47d=106
47d=106-12
47d=94
D=94/47=2
D=2
Now, putting value of d in eqn 1
a+2d=12
a+2(2)=12
a+4=12
A=8
Now, we have to find the 29th term, therefore
a29= 8+(28)2
a29= 8+56
A29=64
Therefore, 29th term is 64.
Hope it will help you!
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