In an examination, 91% students passed
If 18 students failed, find how many
students appeared in the examination
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In an examination, 91% students passed
If 18 students failed, find how many
students appeared in the examination
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Given :-
To Find :-
Solution :-
Let students appeared in the examination be x
Students failed = 100% - 91% = 9%
No. of students failed = 9/100 × x = 18
x = 18 × 100/ 9
x = 2 × 100
x = 200
Hence, 200 students appeared in the examination.
Answer:
Total no. of students appeared in examination is 200.
Step-by-step explanation:
Solution
Let the total number of students be x.
When x ( the total no. of students ) is subtracted from 91% of x, it becomes 18.
Therefore,
x-(91% of x) = 18
➡️x-(91/100×x)=18
➡️x-91/100x=18
➡️100x-91x/100=18
➡️9x/100=18
➡️x=18×100/9
➡️x=200
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Total no. of students appeared in examination = 200
So, 200-(91% of 200)
200-(91/100×200)
=200-182
=18
So the the total no. of students appeared in examination is 200.