in an exmination a student gets 32% marks adn fails by 20 marks . another student gets 42% marks and gets 30 makrs more than the minimum pass marks. find the maximum marks and the pass perentage.
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in an exmination a student gets 32% marks adn fails by 20 marks . another student gets 42% marks and gets 30 makrs more than the minimum pass marks. find the maximum marks and the pass perentage.
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Step-by-step explanation:
Let the maximum mark be x
ATQ,
32% of x+20 = 42% of x-30
32x/100+20=42x/100-30
32x/100-42x/100=-30-20
-10x/100=-50
x=-50×100/-10
=-5000/-10
=500
Answer:
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