In an insulated container 1 mole of a liquid. molar
volume 100 ml at 1 bar. Liquid is steeply taken to
100 bar, when volume of liquid decreases by 1 ml.
Find AH for the process.
1) 7900 bar ml 2) 8900 bar ml
3) 9900 bar ml 4) 10900 bar ml
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In an insulated container 1 mole of a liquid. molar
volume 100 ml at 1 bar. Liquid is steeply taken to
100 bar, when volume of liquid decreases by 1 ml.
Find AH for the process.
1) 7900 bar ml 2) 8900 bar ml
3) 9900 bar ml 4) 10900 bar ml
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Answer:
(3)
Explanation:
Refer image :ΔH by some reaction that happend inside is used for :
(a)increasing internal energy of gas due to which pressure exists. and,
(b)work done to decrease volume of liquid.
Hope it helps.........!
Answer:
Here you go ..........
Explanation:
given that 100ml of liquid was initially at 1bar and the volume becomes 99ml when pressure was increased to 100bar
ΔH = ΔU + ΔPΔV
ΔU = q + w
= 0 + -P(external pressure) x ΔV
= -100(99-100)
= -100(-1)
= 100bar ml
Now ΔH = ΔU + (P2V2 - P1V1)
= 100 + {100(99) - 1(100) }
= 100 + 9900 - 100
= 9900bar ml
Hope you will find this helpful.
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