in cyclic quadrilateral ABCD ,angle ABD=70°and angle BCD=100°.find angle ADB
Share
in cyclic quadrilateral ABCD ,angle ABD=70°and angle BCD=100°.find angle ADB
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
ANS is 30 hope it helps do rate me up if it is correct
Step-by-step explanation:
DCB+DAB=180
DAB=180-100=80
in triangle ABD
DAB+BDA+ABD =180
BDA=180-(80+70)
=180-150
=30