In Duma's method 0.52g of an organic compound. On combustion gave
68.6 ml N2 at 270
c and 756 mm pressure. What is the percentage of
nitrogen in the compound.
full solution plz
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In Duma's method 0.52g of an organic compound. On combustion gave
68.6 ml N2 at 270
c and 756 mm pressure. What is the percentage of
nitrogen in the compound.
full solution plz
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Explanation:
Organic compound
DumasMethod
→
N
2
+ other product
volume of N
2
.V=68.6ml
pressure P=76mmHg=1atm
Temprature T=273+27=300k
n=
RT
Pv
=
0.0821×300
1×68.6×10
−3
=2.785×10
−2
amount of nitrogen 2.785×10
−2
×28=0.078
% of nitrogen =
0.52
0.078
=14.93%