in fig., CD=BE AND BD=CE. PROVE THAT AB=AC
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Step-by-step explanation:
In triangle BCD and triangle BCE ,
CD = BE (given)
BD = CE (given)
BC = BC (common)
So, triangle BCD is congruent to triangle CBE (by SSS)
Therefore , by CPCT ,
angle BCD = angle EBC
As these two angles are equal we know that triangle ABC is an isosceles triangle.
Therefore, AB = AC
Hence proved.
Hope it helps.