in figure 9.14, find x:
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in figure 9.14, find x:
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Answer:
110°
Step-by-step explanation:
In triangle TQP, ∠TQP = 180° - (30° + 35°)
= 180° - 65° = 115°
∴ ∠SQR = 180° - 115° = 65° (linear pair)
By exterior angle property, x = 65° + 45° = 110°