in figure ABCD is cyclic quadriaemt angleAOC=50°, Find angleADC,angleABC,angleOAC,angleOCB
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in figure ABCD is cyclic quadriaemt angleAOC=50°, Find angleADC,angleABC,angleOAC,angleOCB
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Answer:
∠AOC=100°
ABCE is a cyclic quadrilateral.
∠AEC=21∠AOC=50° [ Since as angle made by the chord at the surface of the circle is half of the angle made by the same chord at the center]
In quadrilateral ABCE;
∠AEC+∠ABC=180°⟹∠ABC=130° [ Since in a cyclic quadrilateral sum of diagonal angle is 180°]
∠ABC+∠CBD=180°
⟹∠CBD=50°
Hence;
∠CBD=50° and
∠ABC=130°
Step-by-step explanation:
angle = 130
[tex] \alpha \beta [/tex]