In figure ∠BAC = 90° and AD ⊥ BC. Then (а) BD.CD = BC²
(б) AB.AC = BC²
(c) BD.CD = AD²
(d) AB.AC = AD²
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In figure ∠BAC = 90° and AD ⊥ BC. Then (а) BD.CD = BC²
(б) AB.AC = BC²
(c) BD.CD = AD²
(d) AB.AC = AD²
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