In figure, if AB ∥ CD , ∠APQ = 500° and ∠PRD = 1270°
, find x and y.
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In figure, if AB ∥ CD , ∠APQ = 500° and ∠PRD = 1270°
, find x and y.
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Answer:
Given,
AB || CD, ∠APQ = 500° and ∠PRD = 1270°
Find,
the value of x and y.
Step-by-step explanation:
SO,
=> ∠PQR=∠APQ (Alternate angle)
=> x=50°
=> ∠PRQ+∠PRD=180°
=> ∠PRQ+127° =180°
=> ∠PRQ=180° −127° =53°
=> ∠PQR+∠QPR+∠PRQ=180°
(Angle sum property of trianlge
=> x+y+53° =180°
=> 50° +y+53° =180°
=> y=180° −103° =77°
Hence,
x value is 50° and y value is 77°
Step-by-step explanation:
Using Trigonometric identities: Sin2x = 1- Cos2x
Sin2x = 1 – (4/5)2
= 1 – 16/25
= (25 – 16) / 25
= 9/25
Sin x = 9/25−−−−√
= 3/5