In figure,adjoining LA= (2x+ 5°,LB= (x + 2)° and LCD = 109° then the value of x the is
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In figure,adjoining LA= (2x+ 5°,LB= (x + 2)° and LCD = 109° then the value of x the is
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\begin{gathered} \angle ACD = \angle C = 109° \\ \\ Sum \: of \: all \: angle \: of \: triangle = {180}^{\circ} \\ \\ 2x +5 + x +2 + 109 = 180 \\ \\ 3x + 7 = 71 \\ \\ 3x = 64 \\ \\ x = {21.5}^{\circ} \\ \end{gathered}
∠ACD=∠C=109°
Sumofallangleoftriangle=180
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2x+5+x+2+109=180
3x+7=71
3x=64
x=21.5
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Answer:
[tex]
\huge\red{A}\blue{N}\green{S}\orange{W}\pink{E}\purple{R}[/tex]
[tex]As per the diagram, lines CD∣∣EF and CE is transveral.
We know that sum of interior angles is equal to 180o
∠ECD+∠CEF=180o
∠ECD+130o=180o
∠ECD=180−130o
∠ECD=50o
As per the diagram, lines AB∣∣CD and CA is transveral.
We know that alternate angles are equal.
∠BAC=∠ACD
∠BAC=∠ACE+∠ECD
70o=∠ACE+50o
20o=∠ACE
∴∠ACE=20o
[/tex]