In four years' time, Kim's father will be three times as old as Kim. Six years ago, her father was seven times as old as her. By letting x and y be Kim's present age and Kim's father's age respectively, form two equations to find Kim's present age.
In four years' time, Kim's father will be three times as old as Kim. Six years ago, her father was seven times as old as her. By letting x and y be Kim's present age and Kim's father's age respectively, form two equations to find Kim's present age.
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Answer:
Let x and y be the present age of father and his son.
According to the question,
x−5=7(y−5)
x=7y−30.....(1)
Also,
x+5=3(y+5)
x+5=3y+15
7y−30+5=3y+15(From (1))
7y−3y=15+25
⇒y=
4
40
=10
Substituting the value of y in equation (1), we have
x=7×10−30=70−30=40
Hence the present age of father and his son is 40 and 10 years respectively.
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