In right-angled triangle ABC at angles B, sin A is equal to (A)-cos A (B)cos C (C)sin C (D) none of these
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In right-angled triangle ABC at angles B, sin A is equal to (A)-cos A (B)cos C (C)sin C (D) none of these
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Answer:
(B)
Step-by-step explanation:
In a right angled triangle ABC , sinA = (90°-C)=cos C
JAI SHREE KRISHNA