in the adjoining figure ab is a straight line find the value of x find angle AOC, angle COD,and angle BOD
in the adjoining figure ab is a straight line find the value of x find angle AOC, angle COD,and angle BOD
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➡Given that A B is a straight line,
⏪Using the property , the sum of angles on a straight line =180
= 3x +7 +2x -19+ x = 180
= 6x= 180+12
=6x = 192
= x= 192/6
= 32
Hence , the angles are
x=32
3x+7 = 96+7
= 103
2x-19= 64-19
=45
➡Hence angles are 45, 103 and 32.
Hope it helps you ✌✌
Given : AB is a straight line .
To Find : the value of x
∠AOC , ∠COD, ∠DOB
Solution:
∠AOC + ∠COD + ∠DOB = 180° ( as AB is straight LIne)
∠AOC = 3x + 7
∠COD = 2x - 19
∠DOB = x
∠AOC + ∠COD + ∠DOB = 180°
=> 3x + 7 + 2x - 19 + x = 180°
=> 6x - 12 = 180°
=> 6x = 192°
=> x = 32
∠DOB = 32°
∠AOC = 3x + 7 = 3(32) + 7 = 103°
∠COD = 2x -19 = 2(32) -19 = 45°
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