In the adjoining figure, OPQRS is a trapezium. SR || PO. ZS 45°, ZR 30°,
PQ=4, QR = 12 then find the length of SR. plzz answer me fast..
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In the adjoining figure, OPQRS is a trapezium. SR || PO. ZS 45°, ZR 30°,
PQ=4, QR = 12 then find the length of SR. plzz answer me fast..
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Step-by-step explanation:
PQ will be equal to AB .
PQ=AB=4
NOW IN TRAINGLE BQR angle q will be 60.
BR= 12cos(30).
QB=12sin(30)
and
QB=PA
THEREFORE PA=12sin(30)
In traingle PAS
angle p will also be 45.
son trangle PAS will isosceles
SA=PA
we know PA=12sin(30)
therefore SA=12sin(30)
so finally.
SR= SA+AB+BR
SR=12sin(30)+4+12cos(30)
SR=6+4+6root(3)
SR=10+root(3)
Given : PQRS is a trapezium. SR ||PQ. ∠S=45°, ∠R=30°
PQ = 4
QR = 12
To Find : Length of SR
Solution:
Sin 30° = BQ/ RQ
=> 1/2 = BQ/12
=> BQ = 6
PQ = BQ = 6
Cos 30° = BR/ RQ
=> √3/2 = BR/12
=> BR = 6√3
AB = PQ = 4
Tan 45° = PA/AS
=> 1 = 6 / AS
=> AS = 6
SR = AS + AB + BR
= 6 + 4 + 6√3
= 10 + 6√3
= 20.39
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