In the figure, ,∆ ~ ∆. If . AE=10cm, BC=3.5cm and DE =7cm then AC=
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In the figure, ,∆ ~ ∆. If . AE=10cm, BC=3.5cm and DE =7cm then AC=
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Since Δ AHK ∼Δ ABC
So ACAK=BCHK
So AC =HKAK×BC=710×3.5=5cm