In the figure 'O' is the centre .ABC is an equilateral triangle . find angle BAC and angle ABO
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In the figure 'O' is the centre .ABC is an equilateral triangle . find angle BAC and angle ABO
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Answer:
angle BOC is equal to 120 degrees
Step-by-step explanation:
triangle ABC is an equilateral triangle (given)
therefore angle ABC = angle BAC = angle ACB = 60 degrees
angle BOC = 2(BAC). becauseTheorem 8 : The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.
= 2(60)
= 120degrees
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Answer:
< BAC = 60° and < ABO = 30°
Step-by-step explanation:
Since the triangle ABC is an equilateral triangle,
< ABC = 60°
< BAC = 60° & < BCA = 60°
Join OA. Then consider triangle ABO.
< BOA = 120° ( The angle made by an arc of a circle on the alternative arc is half the angle made by it's centre. Here < BCA = 60° )
Therefore, In ∆ ABO,
< ABO = < BAO = (180° - 120°) / 2 ( Since the sides are equal (radius OB = OA) it's corresponding
angles are also equal)
= 60° / 2
= 30°
Hence the Result