In the given fig. DE || BC, ∟ADE =70° and ∟BAC=50°, then angle ∟BCA = ______
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In the given fig. DE || BC, ∟ADE =70° and ∟BAC=50°, then angle ∟BCA = ______
Please give me Correct answer otherwise Reported.....
Give follow ,For follow back..........
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∠BCA = 60°
GIVEN
ABC is a ∆
DE || BE
∠BAC = 50°
∠ADE = 70°
TO FIND
∠BCA
SOLUTION
We can simply solve the above problem as follows-
Since,
DE || BE
So, According to corresponding angle theoram,
∠ADE = ∠ABC = 70°
Now,
In ΔABC
We know that sum of all the angles of a triangle is 180°
So,
∠BAC + ∠ABC + ∠ACB = 180°
50 + 70 + ∠ACB = 180°
120° + ∠ACB = 180
∠ACB = 180-120 = 60°
Hence, ∠BCA = 60°
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