in the given figure L||m||n. p|l . if <BAC = 55°, find the value of x,y,z
plzz answer it ....
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in the given figure L||m||n. p|l . if <BAC = 55°, find the value of x,y,z
plzz answer it ....
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Answer:
L parallel to n hence angle BEA = angle EAC
90 degree = angle EAC
therefore angle EAC = 90 degree
given angle BAC = 55 degree
angle EAC = angle BAC+anglePAB
90 degree = angle BAC + angle PAB
angle PAB =( 90 -55 ) degree
= 35 degree
angle PAB=Z
therefore angle z=35 degree
angle Z +angle AFD + angle FDA=180 degree (triangle sum property)
35+90+angle FDA= 180 degree
angle FDA = 180 - 125=75degree
angle FDA+angle y = 180 degree ( exterior angle property)
angle y= 180 - 75 = 125 degree
therefore y= 125 degree
angle y=angle x since parallel to m
therefore x = 125 degree
X=125 degree
Y=125 degree
Z=35 degree.
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