In the old days how were the following estimated:
(a) A day _____________
(b) A month ___________
(c) A year _____________
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In the old days how were the following estimated:
(a) A day _____________
(b) A month ___________
(c) A year _____________
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Answer:
x
2
×x
6
=x
2+6
=x
8
{x}^{5} \div {x}^{3} = {x}^{5 - 3} = {x}^{2}x
5
÷x
3
=x
5−3
=x
2
{( {x}^{2} })^{4} = {x}^{8}(x
2
)
4
=x
8
Answer:
b option is correct dear