In the triangle, AC bisects DAB as well as DCB.
i) Is ∆BAC ≅∆DAC?
ii) Is AB = CD? Give reasons.
iii) Is CD = CB?
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In the triangle, AC bisects DAB as well as DCB.
i) Is ∆BAC ≅∆DAC?
ii) Is AB = CD? Give reasons.
iii) Is CD = CB?
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Answer:
Hope this helps
Step-by-step explanation:
So
i) In triangle BAC and DAC
AC=AC [ Common ]
angle ACD=angle ACB [AC bisects triangle DAB making the angles equal to 90 degree]
CD=CB [AC bisects triangle DAB]
triangle BAC=triangle DAC [SIDE-ANGLE-SIDE OR S.A.S property of congruency]
ii) AB=AD [C.P.C.T.E]
iii) CD=CB [AC bisects triangle DAB]