In triangle, ABC is an Isosscoles right-angled triangle in which angle A=90 degree, find angle B
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In triangle, ABC is an Isosscoles right-angled triangle in which angle A=90 degree, find angle B
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Answer:
Given,
\DeltaABC is an isosceles triangle
Right-angled at C [\angle C = 90\degree]
AC = 4cm
AB = ?
\DeltaABC = isosceles \Rightarrow AC = BC = 4 cm
AB = \sqrt{AC^2 + BC^2}
AB = \sqrt{4^2 + 4^2}
AB = \sqrt{16+ 16}
AB = \sqrt{32}
AB = 4\sqrt{2}