in triangle abc the external bisectors of angle abc and angle acb meets at o if angle boc is equal to 45 degree then angle BAC is
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in triangle abc the external bisectors of angle abc and angle acb meets at o if angle boc is equal to 45 degree then angle BAC is
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Answer:
Step-by-step explanation:
In △ABC,
∠ABC+∠ACB+∠BAC=180
∠ABC+70+50=180
∠ABC=60 ∘
∠OCB= 2 1
(180−∠ACB)
∠OCB= 2 1
(180−50)
∠OCB=65 ∘
∠OBC= 2 1
(180−∠ABC)
∠OBC= 2 1
(180−60)
∠OBC=60 ∘
In △OBC, ∠OCB+∠OBC+∠BOC=180
65+60+∠BOC=180
∠BOC=180−125
∴∠BOC=55
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