in what ratio does the point (-4,6) divide the line segment joining the points A(-6,10) and B(3,-8)?
in what ratio does the point (-4,6) divide the line segment joining the points A(-6,10) and B(3,-8)?
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Answer:
x = mx2 + nx1/m+n
-4= k3 + (-1)/k+1b. (let the ratio be k:1)
-4k -4 = 3k -1
-7k = 3
k = 3/-1
or 3:1 externally