Integrate from -5 to 5 |x+2| dx
please give me the steps also
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Integrate from -5 to 5 |x+2| dx
please give me the steps also
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Steps in evaluating the integral of complementary error function?
integration special-functions
Could you please check the below and show me any errors?
∫∞xerfc (t) dt =∫∞x[2π−−√∫∞te−u2du] dt
If I let dv=dt and u equal the term inside the bracket, and do integration by parts,
∫u dv =uv−∫v du
v=t and du becomes
−2π−−√e−t2
This was obtained from using the Leibniz rule below,
ddt[∫baf(u)du] =∫baddtf(u)du+fdbdt−fdadt
Then,
ddt[2π−−√∫∞te−u2du] =2π−−√[∫∞tddt(e−u2)du+e−∞2∗0−e−t2∗1]=2π−−√[0 + 0 −e−t2]
Is the first and second term going to zero correct? The upper limit b=infinity, and is db/dt=0 in the second term correct?
The integral becomes
[ t 2π−−√∫∞te−u2du ]∞x+∫∞xt[2π−−√e−t2] dt=
[ t 2π−−√∫∞te−u2du ]∞x−[1π−−√e−t2]∞x=
[0− x 2π−−√∫∞xe−u2du ]−[0−1π−−√e−x2]=