integration of tanx.
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Answer:
hy ur answer is
Step-by-step explanation:
let I = Integrate tanx dx
= integrate sin x / cos x dx
put cos x = t
therefore -sinx dx = dt
or sin x dx = -dt
I= - integrated dt/t
= - log |t| + c
again
=log secx + c
because -logx=1/logx
hope it helps u
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