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q-3 please do it right now
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The probability that two different friend have different birthdays (ignoring a leap year) is : a) 364/365. b) 1/365.
Probability=Favourable outcomes/Total outcomes
Total outcomes=365
P( two friends having different birthday)=1-[P(event of having same birthday)]
probability having same birthday =1/365
•.• probability having different birthdays=
=1-1/365
=365-1/365
=364/365
ANSWER..
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